Tuesday, December 14, 2010

Double replacement reactions- Cu(NO3)2 + 2NaOH ----> Cu(OH)2 + 2NaNO3 and Part C- Cu(OH)2 ----> CuO + H2O

Cu(NO3)2 + 2NaOH ----> Cu(OH)2 + 2NaNO3

This is the blue jelly like cupric nitrate solution
(Double replacement reaction)
The driving force is the formation of a solid.
Part C- Cu(OH)2 ----> CuO + H2O

It is changing into black cupric oxide
(Double replacement reaction)
The driving force is the formation of a solid and the formation of H2O

Single Replacement Reaction- Zn + CuSO4 ----> ZnSO4 + Cu

Zn + CuSO4 ----> ZnSO4 + Cu


Stirring the Zinc in the Cupric  Sulfate Solution
(single replacement reaction is occuring; the zinc is replacing the copper in the cupric sulfate)
The driving force is the transfer of electrons.

Monday, December 13, 2010

Striving For Accuracy

When measuring we always got down eye level to make sure the bottom of the meniscus was right on the amount we needed

Washing the sides of the beaker to make sure all the copper was in the solution and not stuck to the side

We washed the graduated cylinder with distilled water to be sure that there was no other solution in it

When we removed the leftover pieces of Zinc we washed the pieces to make sure all the copper was off.

Part G- Zn + CuSO4 ----> ZnSO4 + Cu

Zn + CuSO4 ----> ZnSO4 + Cu

Just adding the Zinc into the solution


Stirring the Zinc in the Cupric  Sulfate Solution
(single replacement reaction is occuring; the zinc is replacing the copper in the cupric sulfate)


Washing the salts off of the copper

Part F- Cu3(PO4)2 + 3H2SO4 ---> 3CuSO4+ 2H3PO4

Cu3(PO4)2 + 3H2SO4 ---> 3CuSO4+ 2H3PO4

The Blue Cupric Phosphate. Only a little bit because this is our second funnel of it because we re filtered the leftovers from the first time we filtered.
Dissolving the Cupric Phosphate with Sulfuric Acid

Part E- 3CuCl2 + 2Na3PO4 ---> Cu3(PO4)2 + 6NaCl

3CuCl2 + 2Na3PO4 ---> Cu3(PO4)2 + 6NaCl



The Cupric Phosphate in a solid form




The Cupric Cholride Solution

Monday, December 6, 2010

Part D- CuO + 2HCl ----> CuCl2 +H2O

CuO + 2HCl ----> CuCl2 +H2O
The settled black cupric oxide

removing the water from the cupric oxide

Adding Hydrochloric acid to the cupric oxide